Historical story

What day of the week was 3rd April 1946?

The answer is: Wednesday

Explanation:

To calculate the day of the week for any given date, you can use Zeller's congruence formula:

h = (q + 26(m + 1)/10 + k + k/4 + j/4 + 5j) mod 7

Where:

h is the day of the week (0 = Saturday, 1 = Sunday, 2 = Monday, 3 = Tuesday, 4 = Wednesday, 5 = Thursday, and 6 = Friday).

q is the day of the month.

m is the month (3 = March, 4 = April, ..., 12 = December). January and February are counted as months 13 and 14 of the previous year.

k is the year of the century (the last two digits of the year).

j is the century (the first two digits of the year).

For 3rd April 1946, we have:

q = 3

m = 4

k = 46

j = 19

Plugging these values into the formula, we get:

h = (3 + 26(4 + 1)/10 + 46 + 46/4 + 19/4 + 5(19)) mod 7

= (3 + 26(5)/10 + 46 + 11 + 4 + 95) mod 7

= (3 + 130 + 46 + 11 + 4 + 95) mod 7

= (289) mod 7

= 3

Therefore, 3rd April 1946 was a Wednesday.